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好综合的一题啊,AC自动机+DP+非递归矩阵快速幂+二分+逆向思维。
//#pragma comment(linker, "/STACK:1024000000,1024000000")#include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair pii;#define pb(a) push_back(a)#define INF 0x1f1f1f1f#define lson idx<<1,l,mid#define rson idx<<1|1,mid+1,r#define PI 3.1415926535898template T min(const T& a,const T& b,const T& c) { return min(min(a,b),min(a,c));}template T max(const T& a,const T& b,const T& c) { return max(max(a,b),max(a,c));}void debug() {#ifdef ONLINE_JUDGE#else freopen("d:\\in.txt","r",stdin); // freopen("d:\\out1.txt","w",stdout);#endif}int getch() { int ch; while((ch=getchar())!=EOF) { if(ch!=' '&&ch!='\n')return ch; } return EOF;}const int MAX_NODE=150;const int SIGMA_SIZE=26;int ch[MAX_NODE][SIGMA_SIZE];int fail[MAX_NODE];int val[MAX_NODE];int sz;struct Matrix{ ull da[MAX_NODE][MAX_NODE]; Matrix(){memset(da,0,sizeof(da));} Matrix operator * (const Matrix &ans) { Matrix res; for(int i=0;i
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